Question

:)

Answer 1

Is this actually a physics or math project or just a question asking for you to solve for the variable "t"?

Answer 2

you can use basic algebra to solve for t by isolating it, but it will be an equation using L. But that might be all you need to do... sort of depends on what the purpose of this question is.

Answer 3

just have to solve for t.. i think :/ sorry my computer is lagging!

Answer 4

\[L = \frac{ 980t^{2} }{ 4\pi^{2} }\]

Answer 5

yeah, that's it :)

Answer 6

here is an example
http://www.khanacademy.org/math/algebra/solving-linear-equations-and-inequalities/v/solving-for-a-variable

The first step is multiply both sides by 4\(\pi\). Can you do that?

Answer 7

The first step is multiply both sides by 4\(\pi^2\). Can you do that?

Answer 8

hmm, not really.. :///

Answer 9

write \(4 \pi^2\) times on both sides of the equation

Answer 10

okay

Answer 11

like i dont understand it because it has the pi? :/ i suck at math

Answer 12

pi is just a number

if you multiply both sides by 4 pi^2 you get

\[ 4 \pi^2 L = 4 \pi^2 \cdot \frac{980 t^2}{4 \pi^2}\]

Answer 13

now use a simple rule: if you see something divided by itself , it becomes 1.
Does that ring a bell? It makes the right side "simplify"

Answer 14

no it doesnt :(

Answer 15

ahhh, this is confusing to me

Answer 16

Here are some examples

\[ 3\cdot \frac{4}{3} = \frac{3\cdot 4}{3}= \frac{\cancel{3}\cdot 4}{\cancel{3}}=4\]

Answer 17

do you see anything in your problem that "cancels"?

Answer 18

yeah, i get that but it has the pi in the one im doing? :/

Answer 19

so the pi would cancel out?:S:/

Answer 20

\[ 4 \pi^2 L = \cancel{4 \pi^2} \cdot \frac{980 t^2}{\cancel{4 \pi^2}} \]

Answer 21

yeaah, thats what i thought :))

Answer 22

it is a good rule to remember.

now multiply both sides by \(\frac{1}{980} \)

Answer 23

one over what? i can't read that:((

Answer 24

1/980

Answer 25

first write it down:
\[ 4 \pi^2 L \cdot \frac{1}{980}= 980t^2 \cdot \frac{1}{980} \]

Answer 26

k 1 sec

Answer 27

okays (:

Answer 28

the 980's cancel on the right side, right? (that is why we did this)
we get
\[ t^2 = \frac{4\pi^2 L}{980} \]
Do you see how we did that?

Answer 29

ohhh, yeah i did

Answer 30

the 4 pi^2 L is on the top, and when we multiply fractions, it is top times top and bottom times bottom

Answer 31

\[ \frac{4 \pi^2 L}{1} \cdot \frac{1}{980} = \frac{4 \pi^2 L\cdot 1}{1 \cdot 980} = \frac{4 \pi^2 L}{980}\]

Answer 32

I would simplify by dividing the top by 4, and the bottom by 4. Can you do that?

Answer 33

all of the top?:S i dont know how to simplify because the pi is there? do i use 3.14?:/

Answer 34

leave pi alone. if you divide the top by 4 it is doing this
\[ \frac{\cancel{4}\pi^2L}{\cancel{4}}\]

Answer 35

now divide the bottom by 4: 980/4 is 245

we get
\[ t^2= \frac{\pi^2 L}{245} \]

Answer 36

do you know how to "solve" for t?

Answer 37

multiply both sides by 245?:S

Answer 38

im not sureee :(

Answer 39

if you multiply both sides by 245 you would get a 245t^2 (making it more "complicated" )
Have you heard of a square root?

Answer 40

yeaah i have

Answer 41

square roots are how you "undo" squares:

\[ \sqrt{x^2}= x\]

Answer 42

I would take the square root of both sides

Answer 43

can you draw it out for me so i can see what you mean? it makes more sense when you do that:D

Answer 44

I've noticed it's easier to do work when someone else is doing it, too.
try, it won't hurt

Answer 45

it really does help when someone else shows you, but ill draw it on here to see if im right :) im prob not thou ...haha

Answer 46

Just draw a big square root over each side