Suppose that f is continuous and that (-3to3)∫f(z)dz=0 and (-3to6)∫f(z)dz=8
Find (3to6) -∫4f(z) dz.

NOTE: (By -3 to 3 I mean that the -3 is below the integral and the 3 is up or above the integral)

Question

Suppose that f is continuous and that (-3to3)∫f(z)dz=0 and (-3to6)∫f(z)dz=8
Find (3to6) -∫4f(z) dz.

NOTE: (By -3 to 3 I mean that the -3 is below the integral and the 3 is up or above the integral)

anonymous · Answer

think  of them as areas...  the area under f from -3..3 is zero;
                                              the area under f from -3..6 is eight;
so the area under f from 3..6 must be 8

anonymous · Answer

|dw:1354143287330:dw|

anonymous · Answer

|dw:1354143374332:dw|

anonymous · Answer

Oops the area (-3 to 6)∫ f(z) dz=3 not 8 sorry my bad

anonymous · Answer

doesn't change anything but the value

anonymous · Answer

so the area under f from 3to 6 would be 3

anonymous · Answer

yes

anonymous · Answer

what about the negative sign in front of the integral? Does it affect 3 at all?

anonymous · Answer

ohh never mind...i get it. I have to plug in the 3 into the integral and the answer would be -12