determine whether the series converges:
sum(k=1 -> infinity) [1/(1+lnk)]
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OpenStudy (amistre64):
what the limit of lnk as k to inf?
OpenStudy (slaaibak):
even if the n'th term tends to 0, it doesn't say the series converges.
OpenStudy (amistre64):
yeah, was thinking thru the convergence tests :)
OpenStudy (slaaibak):
harmonic series as an example.
OpenStudy (amistre64):
does 1+ln(x) drop faster than x tho?
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OpenStudy (amistre64):
might need to use a comparison test
OpenStudy (anonymous):
yes, that's what i was thinking..
i got -- 1/(1+lnk) > 1/lnk
and i don't know where to go from here or this is even right..
OpenStudy (slaaibak):
it's the other way around.
1/lnk > 1/(1+ lnk)
so if you can determine whether 1/ln k converges, you can say /1(1+lnk) converges. but if 1/lnk diverges, you can't say anything about 1/(1+lnk)
OpenStudy (anonymous):
just use 1/k as a comparison
OpenStudy (anonymous):
would 1/k be less than 1/1+lnk ?
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