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Mathematics 10 Online
OpenStudy (anonymous):

determine whether the series converges: sum(k=1 -> infinity) [1/(1+lnk)]

OpenStudy (amistre64):

what the limit of lnk as k to inf?

OpenStudy (slaaibak):

even if the n'th term tends to 0, it doesn't say the series converges.

OpenStudy (amistre64):

yeah, was thinking thru the convergence tests :)

OpenStudy (slaaibak):

harmonic series as an example.

OpenStudy (amistre64):

does 1+ln(x) drop faster than x tho?

OpenStudy (amistre64):

might need to use a comparison test

OpenStudy (anonymous):

yes, that's what i was thinking.. i got -- 1/(1+lnk) > 1/lnk and i don't know where to go from here or this is even right..

OpenStudy (slaaibak):

it's the other way around. 1/lnk > 1/(1+ lnk) so if you can determine whether 1/ln k converges, you can say /1(1+lnk) converges. but if 1/lnk diverges, you can't say anything about 1/(1+lnk)

OpenStudy (anonymous):

just use 1/k as a comparison

OpenStudy (anonymous):

would 1/k be less than 1/1+lnk ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

that's the point

OpenStudy (anonymous):

great, thanks!! :)

OpenStudy (anonymous):

sure:)

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