integrate ((3x-1)/(x^2-x-1))
\[\int\limits_{}^{}\frac{ 3x-1 }{ x^2-x-1}\]
what is the derivative of the bottom?
2x-1
hmmm, then my first idea wont work
might have to go ahead and partialdecomp it
what is the factorization of the denom?
(x-1/2)^2 -3/4
..... you are not gonna like what the wolf brought up
i been there couldn't make head or tail of it
http://www.wolframalpha.com/input/?i=integrate+%283x-1%29%2F%28x%5E2-x-1%29 this tells me that its goona best be down by decomposition
x^2-x-1 (x-1/4)^2 -5/4 x = 1/4 + sqrt(5)/4 x = 1/4 - sqrt(5)/4 (x -1/4 -sqrt(5)/4) (x -1/4 + sqrt(5)/4) oy that hurts \[3x-1 =A(x -\frac14 -\frac{\sqrt{5}}4)+B(x -\frac14 + \frac{\sqrt{5}}4)\]
when x=1/4 + sqrt(5)/4 \[3(\frac14 + \frac{\sqrt{5}}4)-1 =A(0)+B(\frac{2\sqrt{5}}4)\] \[\frac{2(\frac34 + \frac{3\sqrt{5}}4-1)}{\sqrt5} =B\]
same concept for finding A, then it logs up just fine; but oy what a mess
did i do the factoring right?
isn't it (x-1/2)^2-5/4
yeah, i got 4s underneath and they need to be 2s :/
same mes tho :)
yeah, thx a million
good luck ;)
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