Use the substitution formula to evaluate the integral.
[0 to ln√(3/3)]∫ [3e^(3x) dx]/[1+e^(6x)].

NOTE:(By 0 to ln√(3/3) I mean that the o is below the integral and the ln√(3/3) is up or above the integral)

Question

Use the substitution formula to evaluate the integral. 
[0 to ln√(3/3)]∫ [3e^(3x) dx]/[1+e^(6x)].

NOTE:(By 0 to ln√(3/3) I mean that the o is below the integral and the ln√(3/3) is up or above the integral)

anonymous · Answer

Try setting u = 1+e^(6x) and du=6e^(6x) dx

anonymous · Answer

kk i got Inverse tan (e^3x)....is that correct??

anonymous · Answer

Sorry I was gone. Yes that's correct :). Here you can check it using wolframalpha http://www.wolframalpha.com/input/?i=%E2%88%AB+%5B3e%5E%283x%29%5D%2F%5B1%2Be%5E%286x%29%5D

anonymous · Answer

ooh ok THANKS man!! XD