Question

Find functions f and g so that h(x) = (f∘g)(x).
h(x) = (6x - 14)^8

A. f(x) = 6x - 14, g(x) = x^8
B. f(x) = 6x^8 - 14, g(x) = -14
C. f(x) = x^8, g(x) = 6x - 14
D. f(x) = (6x)^8, g(x) = -14

Answer 1

I'd just try multiplying each option until I I found the right one.

Answer 2

@just.chris
(fog) =/= fg

(fog)(x) = f(g(x))

Answer 3

A is not possible, since h(x) =/= f(g(x)) = 6x^8 -14

B, D is not possible, since g is a constant in B, D which means f(g(x)) = constant which is not the case.

which leaves...

Answer 4

Why can't a function be a constant?

Answer 5

so it's c?

Answer 6

@just.chris
a function can be constant, but in this case ie. f(g(x)) = h(x) = (6x - 14)^8 is clearly not a constant

Answer 7

@alyssababy7
It is C, but do you understand why?

Answer 8

Thanks, findme. I gotta get (fog), (fg), (f.g) nomenclature correct in my head.

Answer 9

np

Answer 10

thank you

Answer 11

np