Question

HELP
Identify the maximum and minimum values of the function y = 3 cos x in the interval [-2π, 2π]. Use your understanding of transformations, not your graphing calculator.

Answer 1

So we know that for \[y=cos(x)\] the min and max are -1 and 1, respsectively.
because we have \[3cos(x)\] instead of \[cos(x)\]
our min and max will be 3 times the original. so -3 and 3

Answer 2

this is because we have a vertical scalar of 3.

Answer 3

So if I wanted the x coordinate for max and min would the max be +-2pi and 0
the min be +-pi
and the zeros be +- 3pi/2 and +- pi/2?