An observer in a small boat is floating on the surface of a large lake with clear, but contaminated water with index of refraction n = 1.38. Nearby is a wooden post emerging from the water which is embedded in the lake bottom, a distance h = 7.20 meters below the water's surface. What is the maximum distance from the post at which the observer would be able to see the bottom of the post?
the answer will be 6.847m
i wanna explain my procedure to solve this problem
\[n=\frac{ 1 }{ \sin \theta _{c} }\]
here n=refractive index of water
\[\theta _{c}=critical \angle\]
\[or, 1.38=\frac{ 1 }{ \sin \theta _{c} }\]
\[or, \sin \theta _{c}=\frac{ 1 }{ 1.38 }\]
\[\theta _{c}=\sin^{-1} \frac{ 1 }{ 1.38 }\]
\[or, \theta _{c}=0.8105084862\]
now
\[\tan \theta=\frac{ 7.20 }{ d }\]
here 7.20m is the length of the woden post d= distance frm the post to observer
\[or, d=\frac{ 7.20 }{ \tan \theta _{c} }\]
\[or, d=\frac{ 7.20 }{ \sin.8105084862 }=6.847m\]
if u need more explanation then u can ask me
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