At what point on the graph of y=(1/2)x^2-(3/2) is the tangent line parallel to the line 4x-8y=5?

Question

anonymous · Answer

where the derivative is equal to $\frac{1}{2}$

anonymous · Answer

can u explain it plz? as in how u go to that point (finding 1/2)

zepdrix · Answer

If you put 4x-8y=5 into slope-intercept form ( y=mx+b ), you can find the slope that you need to be PARALLEL, or in other words, EQUAL to.

Remember, the derivative represents the SLOPE of your function at a particular point. We want to know when that SLOPE is the same as the slope of the linear function they gave us!

anonymous · Answer

the slope of line you are given is $\frac{1}{2}$

anonymous · Answer

if your curve is $y=\frac{1}{2}x^2+\frac{3}{2}$ then the derivative is $y'=x$

anonymous · Answer

then since the derivative is just $x$ you set $x=\frac{1}{2}$ and there is nothing to solve