Question

solve 3csc^2x-4=0

Answer 1

start by adding 4 to both sides then dividing by 4

\[\csc^2(x) = \frac{4}{3}\]

csc = 1/sin

so find the reciprocal of both sides

\[\frac{1}{\sin^2(x)} = \frac{4}{3}...... or ....\frac{\sin^2(x)}{1} = \frac{3}{4}\]

now just solve for x

Answer 2

nope quite chubby you need to find an angle that satisfies the equation

and its an exact value.... ratio so the angle is either 60, 30 or 45... and will occur in 4 quadrants...

Answer 3

It is
3csc²(x) - 4 = 0
3csc²(x) = 4
csc²(x) = 4/3
csc(x) = ±√(4/3)
csc(x) = ±2 / √(3)
cos(x) = ±√(3) / 2
x = π/3, 2π/3, 4π/3, 7π/3

Answer 4

I mean sin(x) not cos(x)

Answer 5

but the idea of the site @chubbybunny is to help rather than giving the whole solution..

and a little tip.... the cosecant of an angle is equal to 1/sin of the angle

Answer 6

I did say that it is sin(x) did I not