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Use the substitution \(r=1-x\) to evaluate \[ \int\frac{x^2(1+x)}{1-x}\,dx \] I have no clue how to do it.
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hmm
i've never seen this used... i'm wondering if it wants you to use r=1-x to find x^2 and 1+x so you have all in terms of r
Yah, I wrote it out, it looks a bit messy to replace all of the pieces. But you end up with just R in the bottom, instead of 1-x. Allowing you to easily break up the top into a bunch of different fractions that are easy to differentiate.
Oh looks like he logged off :3 heh
I figured it out. Just replace all x with 1-r.
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