Question

show that equation: a = V^2_(av) / R is dimensionally correct. i.e. show that the units match on both sides of the equation

Answer 1

[a]=L.T^-2

[v]=L.T^-1
[R]=L
Hence [v^2/R]=[v]^2/[R]=L^2.T^-2/L=L.T^-2=[a]

Answer 2

where L=''unit of length'', T=''unit of time''

Answer 3

and [x]=''dimensions of x''

Answer 4

thank you!