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Physics 23 Online
OpenStudy (anonymous):

How do you calculate inertia?

OpenStudy (anonymous):

Do you perhaps mean the ''moment of inertia''? Or perhaps you mean the ''angular momentum''?

OpenStudy (anonymous):

Wikipedia should help you

OpenStudy (anonymous):

Integrations are needed to compute moment of inertia in the general case, but there exists easy formulae to compute moment of inertia of numerous solids and figures, such as a sphere, a cylinder, a triangle, etc...

OpenStudy (shamim):

\[I=Mr ^{2}\]

OpenStudy (shamim):

here I=inertia M=mass of a body r=distance of a body from the axis. we r going to calculate inertia with respect to this axis

OpenStudy (mayankdevnani):

1 Multiply the mass and square of distance to the rotation axis to calculate the moment of inertia of the point mass. For example, the mass is 2 kg and the distance is 2 m. Hence, I = mr^2 = 2 kg x 2 m x 2 m = 8 kgm^2.

OpenStudy (shamim):

i hv more explanation abt inertia. if u wanna then i will tell u those later

OpenStudy (mayankdevnani):

2 Navigate to the moment of inertia list (see Resources) and find a formula that corresponds to the object shape and the rotation point. In the example with the solid cylinder, you would find that I = 1/2 x mR^2. Note that R is the cylinder radius.

OpenStudy (mayankdevnani):

3 Calculate the moment of inertia using the formula from Step 2. For example, the cylinder mass is 3 kg and its radius is 0.5 m. The moment of inertia would be: I = 1/2 x 3 kg x 0.5 m x 0.5 m = 0.375 kgm^2.

OpenStudy (mayankdevnani):

ok @amaes

OpenStudy (shamim):

but if the body is continuous a big 1 then we hv to calculate inertia for every points within the big body and then we hv to sum all those inertia of each particle. we will get total inertia for the given body

OpenStudy (shamim):

i think @amaes is not following us. ok . talk with u later

OpenStudy (anonymous):

If all you meant was to calculate "inertia" I'd happy to tell you that that's a virtual property and you can't calculate it.

OpenStudy (anonymous):

Thank you Shadowys! That explains my problem!

OpenStudy (anonymous):

lol you're welcome :)

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