V(s,t)=sqrt(t)*e^-s find the second partial derivative of s
i got sqrt(t)*(s)*(e^-s) wrong
\[\huge V(s,t)=\sqrt t \cdot e^{-s}\] \[\huge \frac{\partial V}{\partial s}=\sqrt t e^{-s}\frac{\partial}{\partial s}(-s)\] Hmm you're pretty close to the right answer :)
for the first derivative i got (sqrt(t))*(-s)*(e^-s) is that wrong
Oh second derivative? woops, my bad.
Yes, what is the derivative of -s? should be -1 yes? ^^ Hope that clears things up.
so the first derivative should be sqrt(t)*s*e^-s ?
\[\huge \frac{\partial V}{\partial s}=-\sqrt t \cdot e^{-s}\]
The only thing that changes, is a -1 coming down from the derivative of the exponent :D
so the second derivative should be sqrt(t)*e^-s ?
So another negative came down? Yup sounds correct! :)
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