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Mathematics 7 Online
OpenStudy (anonymous):

V(s,t)=sqrt(t)*e^-s find the second partial derivative of s

OpenStudy (anonymous):

i got sqrt(t)*(s)*(e^-s) wrong

zepdrix (zepdrix):

\[\huge V(s,t)=\sqrt t \cdot e^{-s}\] \[\huge \frac{\partial V}{\partial s}=\sqrt t e^{-s}\frac{\partial}{\partial s}(-s)\] Hmm you're pretty close to the right answer :)

OpenStudy (anonymous):

for the first derivative i got (sqrt(t))*(-s)*(e^-s) is that wrong

zepdrix (zepdrix):

Oh second derivative? woops, my bad.

zepdrix (zepdrix):

Yes, what is the derivative of -s? should be -1 yes? ^^ Hope that clears things up.

OpenStudy (anonymous):

so the first derivative should be sqrt(t)*s*e^-s ?

zepdrix (zepdrix):

\[\huge \frac{\partial V}{\partial s}=-\sqrt t \cdot e^{-s}\]

zepdrix (zepdrix):

The only thing that changes, is a -1 coming down from the derivative of the exponent :D

OpenStudy (anonymous):

so the second derivative should be sqrt(t)*e^-s ?

zepdrix (zepdrix):

So another negative came down? Yup sounds correct! :)

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