Question

Please help!

What is the remainder of (x^3 – 6x – 9x + 3) ÷ (x - 3) ?

A. -51

B. -51/x - 3

C. -17/x

D. -17/x - 3

A, B, C, or D? Please explain (:

Answer 1

i think it will easier if use the "remainder theorema",
f(x) : (x-a), so its remainder is f(a)
now, if f(x) = x^3 – 6x – 9x + 3
then f(3) = .... ?

Answer 2

I have no idea.

Answer 3

just plug x=3, u will get f(3)

Answer 4

f(x) = x^3 – 6x – 9x + 3
f(3) = 3^3 -6(3) - 9(3) + 3 = ....

Answer 5

One sec

Answer 6

-15

Answer 7

Yes?

Answer 8

ok... correct

Answer 9

but, no option there :)

Answer 10

Right, so. Any idea on what the answer might be?

Answer 11

i think there is a typo error above, maybe... is ur question :
x^3 – 6x – 9x + 3 or
x^3 – 6x^2 – 9x + 3 ?

Answer 12

yea, the second term should be -6x^2, right ?

Answer 13

No. Just 6x is the second term.

Answer 14

actually, a polynomial has a ascending order degree :
f(x) = ax^n +- ax^(n-1) +- ax^(n-2) +- ax^(n-3) +- k
why, the polynomial above be x^3 – 6x – 9x + 3, because it can be simplified to x^3 - 15x + 3, right ?

Answer 15

i mean, f(x) = ax^n +- ax^(n-1) +- ax^(n-2) +- ax^(n-3) +- ..... +- k
+-, means can be + or -

Answer 16

if ur question is f(x) = x^3 – 6x^2 – 9x + 3, so f(3) :
f(3) = 3^3 -6(3)^2 -9(3) + 3 = ....
u will get the answer in option :)

Answer 17

Ugh. I'm never gonna find out this freaking answer.