Question

Help with graphing, please :P

Answer 1

Choose the slope-intercept equation of the line that passes through the point (-5, -1) and is perpendicular to y = 5/2x + 2

Answer 2

They have the same slope since they are perpendicular.

so I know (-5, -1) with a slope of 5/2 has something to do with the equation, but what happens next?

Answer 3

they dont have the same slope, that is when they are parallel. For perpendicular the slope is opposite

Answer 4

its a negative reciprocal, so can you figure it out what the slope is from there?

Answer 5

@SephI User Please Respond.

Answer 6

Oh, ok. So I would have a slope of 2/5, and then what?

Answer 7

close.. m=-2/5
then you use your point-interecpt form:
y-y=m(x-x)

Answer 8

y - (-1) = -2/5[(x - (-5)]
y + 1 = -2/5x + 5
y = -2/5x - 4?

^ That's not one of my options. So I did it wrong...

Answer 9

thats close but you need to distribute the (-2/5) to the 5 as well

Answer 10

Why is that?

Answer 11

that is because the x+5 is in parentheses. so the -2/5 applies to both pieces

Answer 12

or (x-(-5)) however you want to think about it

Answer 13

y - (-1) = -2/5[(x - (-5)]
y - (-1) = -2/5x + ???

How would I distribute the 5?

Wouldn't it be -2/5*5
Which is -10/5
= -2?

Answer 14

yes! perfect. so you would have
(y-(-1))=-2/5x-2
then you just need to y by itself

Answer 15

y + 1 = -2/5x - 2
y = -2/5x - 3 - 1
y = -2/5x - 3?

Answer 16

yep! That should be your answer.

Answer 17

It is. thanks