Question

I have a problem here
a^2 + 8a +13 =0 Now I have the answer but I dont understand how they got there, I thought well ok this looks like something I could factor out but I realized you cannot factor it but you can use the quadratic equation and I tried but I got a stupid answer, -3 radical 3 or -5 radical 3

Answer 1

your answer should be -4+sqrt(3) and -4-sqrt(3)

Answer 2

thank you irene, however I had the answer already I just dont know how to get there.

Answer 3

on what grade are you now?

Answer 4

its the first course of college math for me I am a freshman. Its called college algebra withe trig

Answer 5

just use quadratic equation

Answer 6

\[ a^2 + 8a +13 =0\]
\[(\color{red}1)a^2 + (\color{blue}8)a +(\color{green}{13}) =0\]
\[a_{1,2}=\frac{-(\color{blue}8)\pm\sqrt{(\color{blue}8)^2-4(\color{red}1)(\color{green}{13})}}{2\times(\color{red}1)}\]\[\qquad=\quad \dots\]

Answer 7

\[\qquad=\frac{-8\pm\sqrt{12}}{2}\]\[\qquad=\frac{-8\pm\sqrt{2^2\times3}}{2}\]\[\qquad=\frac{-4\times2\pm2\sqrt{3}}{2}\]
\[\qquad=-4\pm\sqrt{3}\]