Find a rational zero of the polynomial function and use it to find all the zeros of the function. f(x) = x4 + 3x3 - 5x2 - 9x - 2
this might be easier to do if you try some of the answer choices
notice that there are a few differences in the options that would either make or break an option; 1, 2, and 3 if any of these makes a zero in the poly, then we know that option is correct, since none of the others contain them. If none of these provide a zero for us, then it has to be the remaining option
do we get a zero when x=1?
No, you get a 1... but I don't know what answer it is. >.<
well, we have two more numbers to test out
the one that works is the correct answer :)
Alright.
f(1) = 1^4 + 3(1)^3 - 5(1)^2 - 9(1) - 2 1 + 3 - 5 - 9 - 2 4 - 16 not equal 0 ; so x=1 is out
can you work this one for me? f(2) = 2^4 + 3(2)^3 - 5(2)^2 - 9(2) - 2
so that means it's not A?
correct, it is not A
f(2)=0 ?
yes it does :) that means that our solution set HAS to have a +2 in it
so it's d?
i would say it is d yes; lets verify that with the wolf to be sure :)
the wolf like it :)
:)
whenever i take a test that is multiple choice; then i know that one of the answers has to be correct; its just a matter of finding the most efficient way of weeding it out
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