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OpenStudy (anonymous):

Q. the graph relates In K vs 1/T for a reaction .the reaction must be :

OpenStudy (anonymous):

|dw:1354201232478:dw| A) exothermic B) endothermic

OpenStudy (anonymous):

which option is correct?

OpenStudy (anonymous):

@ajprincess

OpenStudy (anonymous):

can u hlp me out .plzzz

OpenStudy (ajprincess):

i am really sorry. I have no idea

OpenStudy (anonymous):

can u suggest any one on os to hlp me @ajprincess

OpenStudy (ajprincess):

I am nt sure. i rarely visit chemistry group. So have no idea. Am really sorry.

OpenStudy (anonymous):

@heena

OpenStudy (anonymous):

listen from the graph we find out the how K depends on temperature now we know that on increasing temp favourable for endothermic but here K i increasing on decreasing temp means it exothermic

OpenStudy (anonymous):

might u read some law like on increasing temp exothermic show backward reaction while endothermic show forward reaction

OpenStudy (anonymous):

temp is also increasing

OpenStudy (anonymous):

no its not see 1/T

OpenStudy (anonymous):

i'm nt understanding the graph ?

OpenStudy (anonymous):

do u know wat is k?

OpenStudy (anonymous):

euilibrium constant?

OpenStudy (anonymous):

yes and will u give me the formula of kc

OpenStudy (anonymous):

that is kc=concn of product/concn of react

OpenStudy (anonymous):

ok now here in graph K is increasing on increasing the value of 1/T means temp i decreasing and on deacresing temp and K also increasing then it must be a exothermic process

OpenStudy (anonymous):

in starting its temp. is 1.5 ,2,2.5 so its increasing

OpenStudy (anonymous):

dear its not T u are provided 1/T

OpenStudy (anonymous):

wat is 1/t

OpenStudy (anonymous):

1/T means if the values are given are in increasing order den T is decreasing but if its value of T given in increassing order then T i increasing

OpenStudy (anonymous):

decreasing then increasing

OpenStudy (anonymous):

see whther they written T or 1/T or ask ur teach dey will explain u the difference abu T and 1/T

OpenStudy (anonymous):

okay .

OpenStudy (anonymous):

wait.

OpenStudy (anonymous):

i hav understood it wait i'm posting 2nd question.

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