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Chemistry 10 Online
OpenStudy (anonymous):

variation of log K with 1/T is shown by the following graph .delta H for the reaction will be:

OpenStudy (anonymous):

@heena

OpenStudy (anonymous):

|dw:1354205703104:dw|

OpenStudy (anonymous):

same reason as for previous qn

OpenStudy (anonymous):

a) -19.14 jmol^-1 b)+19.14 J mol^-1 c)+4.606 cal mol^-1 d)-2cal mol^-1

OpenStudy (anonymous):

correct answer is which one & why?

OpenStudy (anonymous):

A

OpenStudy (anonymous):

why or how?

OpenStudy (anonymous):

i dont remeber how but i read this value before and yea main ans will be in -ve

OpenStudy (anonymous):

why its in negative?

OpenStudy (anonymous):

then it -2 also?

OpenStudy (anonymous):

welll it cant be d as 19.14 is uiveral value of something unable to recall srry

OpenStudy (anonymous):

?

OpenStudy (anonymous):

well negative coz og exothermic process give me a sec i ll show u the proof ok let me chck my notes

OpenStudy (anonymous):

ni mil rha sorry

OpenStudy (anonymous):

okay i will get it i hav to ask u one thing that delta H unit is joule ?

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