Question

A box contains 4 black checkers and 8 red checkers. A checker is drawn and replaced. Then a second checker is drawn. Find the probability that both checkers are red.

Answer 1

multiply the probability that the first one is red, times the probability that the second one is red

Answer 2

okay

Answer 3

\[\frac{8}{12}\times \frac{8}{12}\] or maybe
\[\frac{2}{3}\times \frac{2}{3}\]

Answer 4

for the first red the prob is 8/12 and for the second too it is 8/12 (note replacement done)
hence th reqd probability is 8/12 *8/12=4/9

Answer 5

ya it's 4/9 that's what I got thanks guys