Question

Question on Ellipses! Please Help! Just check it for me, I' already answered it! Please?

Answer 1

looks like length of major axis is 10, from -5 to 5
or am i mistaken?

Answer 2

i think am right

Answer 3

because the left hand endpoint of the ellipse is \((-5,0)\) and the right hand endpoint is \((5,0)\) the the distance between those two points is 10 by counting

Answer 4

yup

Answer 5

ok hold on and let me make sure i did not tell you wron g

Answer 6

no what i said was correct

Answer 7

ok lets go a little slower
the first answer was ten
but the foci are not \((-5,0)\) and \((5,0)\)

Answer 8

for the last problem your "co vertex" is correct

Answer 9

for the first question you asked, the ellipse is given by the equation
\[\frac{x^2}{25}+\frac{y^2}{9}=1\] and i know that because \(5^2=25\) and \(3^2=9\) and the center was at \((0,0)\)

Answer 10

to find the foci, you need to compute
\[c^2=a^2-b^2\]
\[c^2=25-9\]
\[c^2=16\]
\[c=4\]

Answer 11

since the center is at \((0,0)\) and the foci are 4 units to the right and left of the center, they are \((-4,0)\) and \((0,4)\)

Answer 12

notice i did not really have to find the equation of the ellipse
you see the 5 and the 3 from your eyes, so you just compute
\[c^2=5^2-3^2\] to get the foci

Answer 13

the first question
your answer to the second question is correct

Answer 14

i have plenty, and i can't even cash them in for valuable prizes, so no worries