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Mathematics 10 Online
OpenStudy (anonymous):

Please help! Linear algebra! Picture attached

OpenStudy (anonymous):

OpenStudy (anonymous):

Just to make sure I know how to do part a and b... The state vector for time t=2 is just p0*T^2, right? It gives a row vector. Not sure about part c and d though

OpenStudy (anonymous):

@Zarkon @amistre64 @eseidl @TuringTest

OpenStudy (anonymous):

Not quite here yet in my Linear Algebra studies, sorry

OpenStudy (amistre64):

i remember something about the markov being a condition that reaches an equilibrium after so many iterations .... but i just aint got the time at the moment to review it again. Ill have more time in about 2 hours hopefully if noone else has hit it up

OpenStudy (amistre64):

T P_{n-1} = Pn is what im vaguely remembering, which means its most likely in error :)

OpenStudy (anonymous):

What's an error?

OpenStudy (amistre64):

.... most likely my memory without reviewing the subject matter

OpenStudy (amistre64):

\[T~P_o=P_1\] \[\left[\begin{matrix}.3&.4&.3 \\ .5&.0&.5\\.5&.5&.0\end{matrix}\right]\left[\begin{matrix}.2\\.3\\.5\end{matrix}\right]=P_1\] \[.06+.08+.06=.2\]\[.15+.00+.15=.3\]\[.25+.25+.00=.5\] so P1 = [ .2 .3 .5 ] \[T~P_1=P_2\]

OpenStudy (amistre64):

Probability that B does not occur means: P(-B) = 1 - P(B)

OpenStudy (amistre64):

http://www.math.ucdavis.edu/~daddel/linear_algebra_appl/Applications/MarkovChain/MarkovChain_9_18/node1.html and yes, it looks like the recursive setsup the \[P_n=T^nP_0\]

OpenStudy (anonymous):

Ok, so for D... the probability that the state at time t=2 is NOT B is .71 I found and the probability at time t=1 was B is .35, so to find the probability for that state at time t=2 is NOT B while state at time t=1 was B would be??? Would it just be .35*.71??

OpenStudy (amistre64):

im thinking its, P1(B) * P2(-B)|dw:1354281565657:dw|

OpenStudy (anonymous):

Thanks!

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