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OpenStudy (anonymous):
how do i find the inverse function of f(x) = ln ( x+3) - 4 ?
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jimthompson5910 (jim_thompson5910):
f(x) = ln ( x+3) - 4
y = ln ( x+3) - 4
x = ln ( y+3) - 4
Now solve for y
OpenStudy (anonymous):
how can i solve ln(y+3)?
jimthompson5910 (jim_thompson5910):
first add 4 to both sides
OpenStudy (anonymous):
ok,,
jimthompson5910 (jim_thompson5910):
how do you undo the natural log function?
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OpenStudy (anonymous):
im not sure
jimthompson5910 (jim_thompson5910):
how do you undo any log function
OpenStudy (anonymous):
well if 5e''x = 11 is = e''x = 11/5?
jimthompson5910 (jim_thompson5910):
use e^x instead of e"x
OpenStudy (anonymous):
so ln(y+3) is y/lm/3?
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jimthompson5910 (jim_thompson5910):
to solve for y in x = ln(y), you raise both sides as exponents with bases of 'e' to get
e^x = e^(ln(y))
but that just turns into
e^x = y
y = e^x
jimthompson5910 (jim_thompson5910):
so here's the complete step by step picture of what's going on
\[\Large f(x) = \ln(x+3) - 4\]
\[\Large y = \ln(x+3) - 4\]
\[\Large x = \ln(y+3) - 4\]
\[\Large x+4 = \ln(y+3)\]
\[\Large e^{x+4} = y+3\]
\[\Large e^{x+4}-3 = y\]
\[\Large y = e^{x+4}-3\]
\[\Large f^{-1}(x) = e^{x+4}-3\]
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