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Trigonometry
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If someone could help i really need this... verify the identities, (sin x+tan x+ tan^3 x)/tan x= cos x + sec^2 x
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Start with the left side, and remember that tan x = sin x / cos x:\[\frac{ \sin x+\tan x+\tan ^3x }{ \tan x }=\]\[\frac{ \sin x+\frac{ \sin x }{ \cos x }+\frac{ \sin ^{3}x }{ \cos ^{3}x } }{ \frac{ \sin x }{ \cos x } }=\]\[ \left( \sin x+\frac{ \sin x }{ \cos x }+\frac{ \sin ^{3}x }{ \cos ^{3}x } \right)*\frac{ \cos x }{ \sin x }=\]\[\cos x+1+\frac{ \sin ^{2}x }{ \cos ^{2}x }=\]\[\cos x+1+\tan ^{2}x=\]\[\cos x+\sec ^{2}x\] And we have verified the equality. If there is anything unclear, please ask, I'll try to explain. ZeHanz
Well, I like doing these kind of probs, but one wonders sometimes: how urgent is it?
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