Ask your own question, for FREE!
Trigonometry 8 Online
OpenStudy (anonymous):

If someone could help i really need this... verify the identities, (sin x+tan x+ tan^3 x)/tan x= cos x + sec^2 x

OpenStudy (zehanz):

Start with the left side, and remember that tan x = sin x / cos x:\[\frac{ \sin x+\tan x+\tan ^3x }{ \tan x }=\]\[\frac{ \sin x+\frac{ \sin x }{ \cos x }+\frac{ \sin ^{3}x }{ \cos ^{3}x } }{ \frac{ \sin x }{ \cos x } }=\]\[ \left( \sin x+\frac{ \sin x }{ \cos x }+\frac{ \sin ^{3}x }{ \cos ^{3}x } \right)*\frac{ \cos x }{ \sin x }=\]\[\cos x+1+\frac{ \sin ^{2}x }{ \cos ^{2}x }=\]\[\cos x+1+\tan ^{2}x=\]\[\cos x+\sec ^{2}x\] And we have verified the equality. If there is anything unclear, please ask, I'll try to explain. ZeHanz

OpenStudy (zehanz):

Well, I like doing these kind of probs, but one wonders sometimes: how urgent is it?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
2 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
2 days ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!