Question

-2p^2-6p+20 Can someone help me factor this problem.? Im so confused.

Answer 1

-2-10p+4p+20

Answer 2

-2(p+5)(p-2)

Answer 3

-2p^2+4p-10p+20

Answer 4

Factor the two out...
-2(p^2 + 3p +10)
Now you can see that
(p^2 + 3p +10) becomes (p+5)(p-2)

Answer 5

Thanks LogicalReason that helped alot.

Answer 6

-2p(p-2)-10(p-2)
(-2p-10)(p-2)
-2(p+5)(p-2)

Answer 7

If you're confused on how to solve these (look at LogicalReason's reply before this).

Multiply the term before p^2, in this case 1, with the term with no x, in this case 10.

Then find two factors of 10 that add up to 3. In this case, that's 5 and -2. Those two numbers become the two numbers in the new equation below:

-2(p+5)(p-2)

Answer 8

Sorry, I had a typo. The two numbers you multiply are actually 1 and -10, so you need to find the two factors that multiply into -10, that when added together equal three. Logical's reply had (p^2 + 3p +10) when it should have been (p^2 + 3p -10).

The factors are still 5 and -2, though. Just read the above comment, but replace 10 with -10 and it'll make more sense.