Question

medal anyone??

What are the real or imaginary solutions of the polynomial equation?
27x^3 + 125 = 0

Answer 1

take the cubic root of both sides.
3x + 5 = 0
x = -5/3

Answer 2

@cwrw238

Answer 3

oh snap didnt see you sorry lol and are you just trying to get x by itself?

Answer 4

you can't do it like that... there may be (actually, there are) imaginary or complex solutions also.

Answer 5

oh jeez.. sounds fun

Answer 6

I'm terrible at factoring polynomials like this, but you can factor out (3x+5) from the polynomial, leaving:

(3x+5)(9x^2 - 15x + 25)

Answer 7

I'm not sure "fun" is the right word!

The first part would lead to a real solution of x = -5/3

The second part has two complex solutions you can get from the quadratic formula.

Answer 8

hahaha i got it now, i have another one too and if you can get it i'll follow and medal you for it

Answer 9

Use the Remainder Theorem to find the remainder when P(x) = x^4 – 9x^3 – 5x^2 – 3x + 4 is divided by x + 3.

Answer 10

@JakeV8

Answer 11

@cwrw238

Answer 12

The Remainder Theorem says that the remainder R is P(a).
Write x+3 as x - (-3). So a = -3. Evaluate P(-3)