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If 6 ∫ f(x) dx 2 ≤ 6 ∫g(x) dx 2 , then f(x) ≤ g(x) for 2 ≤ x ≤ 6 . True False
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This is slightly better, however, still extremely hard to understand I'm not quite getting the question. @__assassin__ do you understand this?
im looking at it but its hard to read the way you typed it
I agree. This is very hard to understand.
\[\int\limits_{2}^{6}f(x)dx \le \int\limits_{2}^{5}g(x)dx\]
wait \[\int\limits_{2}^{6}g(x)dx\]
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I say it is false. Here's a counterexample.|dw:1354227678958:dw| Even though one of the functions has a larger signed area, it can still get smaller than the other function in the interval.
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