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Mathematics 13 Online
OpenStudy (anonymous):

I really don't get this lesson question: Which statement is true for the circle? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/0800/0800_G8_Q29a.gif Its center is at the ordered pair of 1 over 2, minus 1, and the radius is minus five over two units. Its center is at the ordered pair of minus 1 over 2, 1, and the radius is five over two units. Its center is at the ordered pair of 1 over 2, minus 1, and the radius is five over two units. Its center is at the ordered pair of minus 1 over 2, 1, and the radius is minus five over two units.

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (mathstudent55):

The link doesn't work

OpenStudy (anonymous):

it works on mine

OpenStudy (anonymous):

@AccessDenied

OpenStudy (anonymous):

This link works for you because it is on a course website and you have to be logged in to view it, do you know how to take a screenshot?

OpenStudy (anonymous):

umm i think lemme try

OpenStudy (anonymous):

Okay if you need help, reply back with your computer OS(Operating System, Mac or Windows)

OpenStudy (anonymous):

Here's the whole thing as pasted from the lesson

OpenStudy (phi):

a radius is always positive

OpenStudy (anonymous):

okay...?

OpenStudy (phi):

that rules out 2 of your choices

OpenStudy (anonymous):

so it's either B or C, but I still don't know which

OpenStudy (phi):

the (x,y) pair at the center will make the (x-a)^2 and (y-b)^2 terms zero does that make sense?

OpenStudy (anonymous):

not really, no...

OpenStudy (phi):

usually they say (x-h)^2 + (y-k)^2 = r^2 and the center is at (h,k) with radius r

OpenStudy (anonymous):

how do we get h and k?

OpenStudy (phi):

so if you see (x- 1/2) that means the x value of the center is +1/2

OpenStudy (anonymous):

okay

OpenStudy (phi):

in this case you match your equation to the "generic" one match (x-h)^2 + (y-k)^2 = r^2 (x-1/2)^2 + (y + 1)^2 = 25/4

OpenStudy (phi):

matching y-k to y+1 you have to rewrite y+1 as y - (-1) now you see y - k matches y - (-1) and k is -1

OpenStudy (phi):

or remember that you want the y value that makes (y+1)^2 zero. that would be y= -1

OpenStudy (anonymous):

so the Y is -1?

OpenStudy (anonymous):

then it's C? Right?

OpenStudy (phi):

yes.

OpenStudy (anonymous):

Thank you soooooo much! I'm going to go write you a testimonial! haha

OpenStudy (phi):

thank you

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