Please help!!!!!!! I will reward you with e medal just please help!!!!!!!!!!!!
Solve using two different methods. Explain which method you found to be more efficient. a. 3x – 9y = 3 b. 7x – 3y = 20 c. y = 1/2x - 6 6x – 3y = -24 5x + 3y = 16 2x + 6y = 19
I would help you with this but I took this in middle school! and then my freshman year and now im a senior. I forgot. I'm so sorry
Someone will help you though!
=( its ok i just dont know and i want it done but i cant figure it out! But thanks anyway!
i can help
YAY Please help I need help with b and c...
have you taken the first equation and isolated one variable yet?
Substitution method 3x - 9y = 3 Dividing throughout by 3,we get x - 3y = 1 x = 1 + 3y ..... ( i ) 6x - 3y = - 24 .....( ii ) that's all i know
i have no clue what that means @swmchick
actually ignore that
if you look at the two problems, you notice one has a -3y and the other is +3y right?
ya
so would i add both equations together then
so what you can do is set up one giant addition problem that will look like this \[(7x-3y=20)-5x=3y=16\]
exactly. just add all like variables and its easy to solve for x
ok i got x now what do i do to get y?
then all you have to do is plug that value back into any equation to solve for y
now is that substitution?
yes :)
tell me when you got it and we can move to c
ok so for x i got x=3 and for y i got y = -1 2/3 is that correct?
sounds right
to check just plug it into the other equation :)
ok now for c would we do elimination?
Because I ave no clue how to do that lol.
you would do the same thing you did for b. it just requires one more step. you would rearrange the first equation to 1/2x - y = 6 Then multiply that whole equation by -4
you would get -2x=4y=-26
then you can make both of the equations into one big addition problem and solve the same way you did for b
you mean -2x + 4y = -24
yes. sorry. typo
are you all good? :)
ok i am solving right now give me just a second.
can you solve my problem after?
i can try yes.
ok so i got x=11 and y= -1/2 is that right and did we use substitution again?
yeah
KEWL! Thanks ok so give me the link to yours and ill see if i can solve it.
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