Question

is the derivative of e^x is just e^x?
and if i did the derivative of e^x again, nothing change?

Answer 1

yes, it is \(e^x\) all the way down

Answer 2

is that simple XD?

Answer 3

are you trying to find the series for \(e^x\) ?

Answer 4

yeaup haha unless u get a e^2x then u have to pull the 2 out in front like a chain rule

Answer 5

it is a well known series
\[\sum_{k=0}^{\infty}\frac{x^k}{k!}\]

Answer 6

and yeah i was trying to use the Maclaurin series.