Find the derivative:

d/dt (0to Sin t)∫[(1/(4-u^2)][du]

NOTE: What I mean with o to Sin t is that the 0 is below the integral and sin t is up or above the integral.

Question

Find the derivative:

d/dt (0to Sin t)∫[(1/(4-u^2)][du]

NOTE: What I mean with o to Sin t is that the 0 is below the integral and sin t is up or above the integral.

anonymous · Answer

the derivative of the integral is the integrand, plus chain rule

anonymous · Answer

in simple english, take the integrand, replace $u$ by $\sin(x)$ and then multiply the result by the derivative of $\sin(x)$ which is $\cos(x)$

anonymous · Answer

for a final answer I got
 
cost/(4-(sint)^2)

anonymous · Answer

looks good to me

anonymous · Answer

Awesome! Thank you!

anonymous · Answer

yw (easy when you know what to do, right?)

anonymous · Answer

Sure is XP