Question

Find the derivative:

d/dt (0to Sin t)∫[(1/(4-u^2)][du]

NOTE: What I mean with o to Sin t is that the 0 is below the integral and sin t is up or above the integral.

Answer 1

the derivative of the integral is the integrand, plus chain rule

Answer 2

in simple english, take the integrand, replace \(u\) by \(\sin(x)\) and then multiply the result by the derivative of \(\sin(x)\) which is \(\cos(x)\)

Answer 3

for a final answer I got

cost/(4-(sint)^2)

Answer 4

looks good to me

Answer 5

Awesome! Thank you!

Answer 6

yw (easy when you know what to do, right?)

Answer 7

Sure is XP