A body of mass 2 kg, moving on a horizontal surface
with an initial velocity of 4 m/s, comes to rest after 2
seconds. If one wants to keep this body moving on
the same surface with a velocity of 4 m/s, the force
required is
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OpenStudy (mayankdevnani):
is answer is 4N
OpenStudy (dls):
how
OpenStudy (dls):
yes
OpenStudy (mayankdevnani):
first, find acceleration of body is
what is the formula of acceleration of a body???
OpenStudy (dls):
a=v-u/t
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OpenStudy (dls):
arent v & u both4?
OpenStudy (mayankdevnani):
no?
OpenStudy (mayankdevnani):
\[a=\frac{v-u}{t}\]
where u=4 m/s and v=0 m/s
OpenStudy (mayankdevnani):
find accleration?
OpenStudy (dls):
why?
they are saying initial and final velocities should be same..i.e 4m/s it shouldnt change
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OpenStudy (mayankdevnani):
no, your question said that initial velocity is 4 m/s( written in your question) and final velocity is 0 m/s(comes to rest) .
ok @DLS
OpenStudy (mayankdevnani):
Given
u=4 m/s
v=0 m/s
t=2 s
a=v-u/t
a=0-4/2
so find acceleration? can you @DLS