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Show that; y'' = -2x/y^5 , when x^3 - y^3 =1.
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define y' for me
or just take a first derivative of the given equation, and then a second, defining y' will help simplify the second derivative overall
yes
x^3 - y^3 =1 3x^2 - 3y^2 y' = 0 6x - 6y y' - 3y^2 y'' = 0 the rest is simple algebra
That was close, I also had the same answer like yours. But that does not complete the proof.
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im not here to complete your proof, i am here to guide you along the way.
the last setup has all the needed information for you to work with, just algebra your way thru it and simplify the results
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