Question

What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)?
y = 3x + 1
y = x – 3
y = 2x + 5
y = 2x – 5

Answer 1

can you find the slope of the line...?

Answer 2

http://www.algebra.com/algebra/homework/absolute-value/absolute-value.faq.question.174831.html this should help

Answer 3

yes its -2

Answer 4

well then just plot one of your points and keep using your slope.. down two, right one, point. down two right one point. or vice versa up two, left one, point

Answer 5

then use slope int. form y=mx+b where m=slope and b=y-int.

Answer 6

ok, so the slope intercept form of a line is

\[y = mx + b\]

and using your slope you have

y = -2x + b

so to find b pick a point (3, 1) and substitute x = 3 and y = 1 to find b.

then you'll have the equation of the line.

Answer 7

so b=7?

Answer 8

but looking at your choices... your slope calculation is incorrect...

(1 - -3)/(3 - 1)

Answer 9

ohh...

Answer 10

lets get the slope right 1st

Answer 11

I still got -2..

Answer 12

1- (-3) = -4. 3-1= 2. so thats -4/2, simplified to -2/1= -2

Answer 13

1 - -3 = 4 2 negatives make a positive

so the slope is 4/2 or 2


so you have

y = 2x + b substitute x = 3, y = 1

to find b and the equation of your line

Answer 14

so b= -5?

Answer 15

thats it so your line is

y = 2x - 5

Answer 16

omg thank you:D <3333

Answer 17

glad to help