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What is the volume of the solid obtained by rotating the region bounded by the curves y = x^3 - 5x^2 +6x ; y = 2x around the x-axis ?
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y = x^3 - 5x^2 +6x ; y = 2x First check where they both cut each other. x^3 - 5x^2 + 4x = 0 Solve for x. You should get: x = 0 , x =1 , x=4.
Next, Integrate the squared equation with applying limits. Vol of line - vol of curve.
54PI/35
is my correct
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*answer
Im getting 206.8
i mean is that the final answer
Yes. My answer is final too.
Vol under curve = 2048pi/105 Vol under line = 256pi/3
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