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Mathematics 4 Online
OpenStudy (dls):

DE help

OpenStudy (dls):

\[y=\log(x^{2}\sqrt{x^{2}+1})\]

OpenStudy (dls):

I got something like this \[\frac{1}{x^{2}\sqrt{x^{2}+1}} \times 2\sqrt{x^{2}+1} \times 2x\]

OpenStudy (dls):

@ghazi

OpenStudy (ghazi):

there is a bit of editing you should have used product rule

OpenStudy (ghazi):

for (x^2 sqrt{x^2+1})

OpenStudy (dls):

how?:o

OpenStudy (ghazi):

\[\frac{ d(x^2 \sqrt{x^2+1}) }{ dx }=x^2\frac{ d \sqrt{x^2+1} }{ dx }+\sqrt{x^2+1}*2x\]

OpenStudy (dls):

woah :o thanks

OpenStudy (ghazi):

:) YW

OpenStudy (dls):

how did you get dx in the denominator?

OpenStudy (ghazi):

you are differentiating with respect to x

OpenStudy (ghazi):

i can write it as\[\frac{ d }{ dx }(\sqrt{x^2+1}*x^2)\]

OpenStudy (dls):

oh wait equation is messed up lol just asec

OpenStudy (dls):

\[\frac{dy}{dx}=\frac{dlog(x^{2}\sqrt{x^{2}+1}}{dx^{2}\sqrt{x^{2}+1}} \times \frac{dx^{2} \sqrt{x^{2}+1}}{d \sqrt{x^{2}+1}} \] ..so on

OpenStudy (ghazi):

NO

OpenStudy (dls):

i do like this,where i didnt diff. wrt. dx

OpenStudy (dls):

thats how im taught >.>

OpenStudy (ghazi):

you have to differentiate wrt x, you can't diffrentiate wrt to function

OpenStudy (dls):

wth :/ am i taught wrong :S but i was getting all the answers like this

OpenStudy (ghazi):

differentiation is done wrt to a variable basically differentiation tells us rate of change of one variable wrt to another and function is something that tells us the relation between those two variables so we can never get rate of change wrt to a function

OpenStudy (dls):

okay..!

OpenStudy (ghazi):

\[\frac{ d }{ dx }(\sqrt{x^2+1})*x^2+2x* \sqrt{x^2+1}\]

OpenStudy (dls):

okay...clear!

OpenStudy (ghazi):

cool :D

OpenStudy (ghazi):

\[\frac{ d }{ dx } (\sqrt{x^2+1})=\frac{ 1 }{ \sqrt{x^2+1} }*\frac{ d }{ dx }(x^2+1)\]

OpenStudy (ghazi):

there will be a factor of -1/2 multiplied in RHS

OpenStudy (dls):

derivative of sqrt x is 1/2x right :o

OpenStudy (ghazi):

-1/2 x

OpenStudy (dls):

\[\frac{d \sqrt{x}}{dx}= \frac{1}{2 \sqrt{x}}\] does my coaching class suck lol :/

OpenStudy (ghazi):

no they are right let me show you

OpenStudy (dls):

will it be like this: \[\frac{1}{2 \sqrt{x^{2}+1}} \times 2x = \frac{x}{\sqrt{x^{2}+1}} \]

OpenStudy (ghazi):

\[\frac{ d }{ dx } (x)^{-1/2}= \frac{ -1 }{ 2 }(x)^{-1/2-1}\]

OpenStudy (dls):

so how do we have 2 answers

OpenStudy (ghazi):

no we have one, just be careful in calculating power

OpenStudy (dls):

okay..

OpenStudy (dls):

so final answer im getting is

OpenStudy (dls):

\[\frac{1}{x(x^{2}+1}\]

OpenStudy (dls):

\[\frac{1}{x^{2} \sqrt{x^{2}+1}} \times \frac{x}{\sqrt{x^{2}+1}}\]

OpenStudy (ghazi):

\[\frac{ d }{ dx } (\sqrt{x^2+1})=\frac{1 }{ 2 }(\sqrt{x^2+1})^{-3/2}* 2x\] your answer

OpenStudy (dls):

what did you do

OpenStudy (ghazi):

\[\frac{ d }{ dx }(x^n)=nx^{n-1}\] hope you know this formula

OpenStudy (dls):

oh okay!

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