DE help
\[y=\log(x^{2}\sqrt{x^{2}+1})\]
I got something like this \[\frac{1}{x^{2}\sqrt{x^{2}+1}} \times 2\sqrt{x^{2}+1} \times 2x\]
@ghazi
there is a bit of editing you should have used product rule
for (x^2 sqrt{x^2+1})
how?:o
\[\frac{ d(x^2 \sqrt{x^2+1}) }{ dx }=x^2\frac{ d \sqrt{x^2+1} }{ dx }+\sqrt{x^2+1}*2x\]
woah :o thanks
:) YW
how did you get dx in the denominator?
you are differentiating with respect to x
i can write it as\[\frac{ d }{ dx }(\sqrt{x^2+1}*x^2)\]
oh wait equation is messed up lol just asec
\[\frac{dy}{dx}=\frac{dlog(x^{2}\sqrt{x^{2}+1}}{dx^{2}\sqrt{x^{2}+1}} \times \frac{dx^{2} \sqrt{x^{2}+1}}{d \sqrt{x^{2}+1}} \] ..so on
NO
i do like this,where i didnt diff. wrt. dx
thats how im taught >.>
you have to differentiate wrt x, you can't diffrentiate wrt to function
wth :/ am i taught wrong :S but i was getting all the answers like this
differentiation is done wrt to a variable basically differentiation tells us rate of change of one variable wrt to another and function is something that tells us the relation between those two variables so we can never get rate of change wrt to a function
okay..!
\[\frac{ d }{ dx }(\sqrt{x^2+1})*x^2+2x* \sqrt{x^2+1}\]
okay...clear!
cool :D
\[\frac{ d }{ dx } (\sqrt{x^2+1})=\frac{ 1 }{ \sqrt{x^2+1} }*\frac{ d }{ dx }(x^2+1)\]
there will be a factor of -1/2 multiplied in RHS
derivative of sqrt x is 1/2x right :o
-1/2 x
\[\frac{d \sqrt{x}}{dx}= \frac{1}{2 \sqrt{x}}\] does my coaching class suck lol :/
no they are right let me show you
will it be like this: \[\frac{1}{2 \sqrt{x^{2}+1}} \times 2x = \frac{x}{\sqrt{x^{2}+1}} \]
\[\frac{ d }{ dx } (x)^{-1/2}= \frac{ -1 }{ 2 }(x)^{-1/2-1}\]
so how do we have 2 answers
no we have one, just be careful in calculating power
okay..
so final answer im getting is
\[\frac{1}{x(x^{2}+1}\]
\[\frac{1}{x^{2} \sqrt{x^{2}+1}} \times \frac{x}{\sqrt{x^{2}+1}}\]
which is wrong :/ http://www.wolframalpha.com/input/?i=derivative+of+log%28x%5E2%28sqrt%28x%5E2%2B1%29%29%29
\[\frac{ d }{ dx } (\sqrt{x^2+1})=\frac{1 }{ 2 }(\sqrt{x^2+1})^{-3/2}* 2x\] your answer
what did you do
\[\frac{ d }{ dx }(x^n)=nx^{n-1}\] hope you know this formula
oh okay!
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