Question

How do you find the curl of function f(x,y)=1111+(x/1100)^2

Answer 1

\[curl f=\left[\begin{matrix}i & j & k \\ \frac{\partial }{\partial x}& \frac{\partial }{\partial y}& \frac{\partial }{\partial z}\\ f_{x} & f_{y}& f_{z}\end{matrix}\right]\]

Answer 2

in your case f looks like scalar field. So there is no curl

Answer 3

is that fx , fy and fz in 3rd row are you sure? isn't it cifficient of i j and k?

Answer 4

that's what fx , fy and fz are. They are the components of f

Answer 5

f should be a vector, if you whant to find it's curl. So it so it should look somthing like this:
\[f(x,y)=f_{x} i +f_{y} j\]

Answer 6

Here f describes pressure vector field in 2 dimension

Answer 7

When you make contour plot you can see, pressure increasing from higher to lower region

Answer 8

DO you know how to write this equation as vector field? I am given only this equation

Answer 9

as I said befor. This equation asigns a numerical (scalar) value to every point in xy plane. So there is no vector field. The only vector field asociated with this sclara field is the field of grad f. But the curl(grad f)=0 always. That's all there is about this.

Answer 10

ok thnks