Question

Use trig identities to evaluate indefinite integration of:
[4 sin(x) + 4 cos(x)]^2 dx

Answer 1

16cos(x)-16sin(x)

Answer 2

how'd you find it?

Answer 3

wait what? that's wrong

Answer 4

the question is looking for integration

Answer 5

16(cos(x)+sin(x))^2dx

Answer 6

16(cos(x)^2+sin(x)^2+2sin(x)cos(x))dx

Answer 7

cos^2+sin^2=1

Answer 8

wait 16(cosx + sinx)^2 is not the same as [4sinx +4cos]^2

Answer 9

no probl. i figured it out but thanks for trying :)

Answer 10

it s same

Answer 11

because [4(sinx +4cos)]^2
16(sinx +cos)^2

Answer 12

my typing wrong

Answer 13

but answer is 32cos^2-32sin^2
32(1-2sin(x)^2)