Question

Calculating the

1) Attraction force
2) Repulsion force

Of two permanent dipoles?

I thought I should use Coulomb's law but I what should I do about q1 and q2 ?!

Answer 1

@Vincent-Lyon.Fr

Answer 2

@Carl_Pham

Answer 3

@Jemurray3 @experimentX @ghazi @TuringTest

Answer 4

There is a formula for that, but do you know it and are you allowed to use it?

If not, use field created by dipole No1 and work out its action on both charges (q;-q) of dipole No2 separated by distance a. Then make a approach zero keeping P = qa constant.

Answer 5

@Vincent-Lyon.Fr No I don't... Please share with me the formula!

Answer 6

@Vincent-Lyon.Fr BASED on the "If not, use field created by dipole No1 and work out its action on both charges (q;-q) of dipole No2 separated by distance a. Then make a approach zero keeping P = qa constant." could you give use it using a random example? It helps a lot in my understanding!
Thanks!

Answer 7

So Q 1 would be dipole 1 - Q 2 that is dipole 2?!

Instead of using the "magnetic field" wouldn't a pull force be more better?

Answer 8

I do not understand you.

In your qn, you state Coulomb's law. So I inferred you were talking about an electrostatic dipole, and now you are talking about a magnetic one. Which is it?

Force of attraction by dipole 1 on dipole 2 is :

\(\vec F = \vec\nabla (\vec P_2 . \vec E_1) \)

Answer 9

You can also solve using the 4 Coulomb forces between the charges.

Answer 10

Must go, will be back later.

Answer 11

Thanks @Vincent-Lyon.Fr I was talking about a magnetic dipole sorry...

Answer 12

to all IM REFERRING TO A MAGNETIC DIPOLE (A PERMANENT MAGNET).

Answer 13

As there are no magnetic "charges", you must use the formula I provided, adapted form magnetic dipoles:

\(\vec F = \vec\nabla (\vec M_2 . \vec B_1)\)

where \(\vec M_2\) is magnetic moment of the dipole which is affected, and \( \vec B_1\) is the field created by the acting dipole.

Answer 14

Ow ok so this the F of Dipole 1 acting on Dipole 2?!
Btw I mean a magnetic dipole(magnet). Now does this formula express the F of both dipoles of just on? Could you explain more? Tis should include 2 dipoles not only one :S Im confused...