Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

I need help with this question Anyone please....

OpenStudy (anonymous):

Assume that the population of heights of male college students is approximately normally distributed with mean  of 72.15 inches and standard deviation  of 6.39 inches. A random sample of 96 heights is obtained. Show all work. (A) Find P(x>73.25) (B) Find the mean and standard error of the xˉ distribution (C) Find P(xˉ > 73.25) (D) Why is the formula required to solve (A) different than (C)?

jimthompson5910 (jim_thompson5910):

for A and C, you need a calculator or a table

jimthompson5910 (jim_thompson5910):

for part b), the mean is xbar = 72.15 (since the mean of the xbar distribution is the population mean) and the standard error is sigma/sqrt(n) = 6.39/sqrt(96) = 0.6521766

jimthompson5910 (jim_thompson5910):

in part D, the difference between the two formulas comes from the fact that the standard deviations are different (in the population, it's 6.39, but in the xbar distribution, it's 0.6521766)

OpenStudy (anonymous):

okay thanks I see what your saying now

jimthompson5910 (jim_thompson5910):

np

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!