Question

A ladder of length L = 2.8 m and mass m = 19 kg rests on a floor with coefficient of static friction μs = 0.48. Assume the wall is frictionless.
1)What is the normal force the floor exerts on the ladder?
2)What is the minimum angle the ladder must make with the floor to not slip?
A ladder of length L = 2.8 m and mass m = 19 kg rests on a floor with coefficient of static friction μs = 0.48. Assume the wall is frictionless.
1)What is the normal force the floor exerts on the ladder?
2)What is the minimum angle the ladder must make with the floor to not slip?
@Physics

Answer 1

the weight of the lader is W=mg=19*9.8=186.2N

Answer 2

we know frm newtons third law of motion, normal force exerted by the floor on the ladder = the weight of the ladder=186.2N

Answer 3

if u need more explanation plz ask me

Answer 4

u know every action has an equal n opposite reaction. its newtons 2nd law of motion

Answer 5

so the weight of the ladder W is a force exerted by the ladder on the floor is equal n opposite to the force exerted by the floor on the ladder. the force on the ladder is called reaction force R. so W=R

Answer 6

i talked abt question 1 above

Answer 7

now question2

Answer 8

we know limiting static frictional force \[F=\mu _{s}R=0.48 \times mg=0.48 \times 19 \times 9.8=89.38N\]

Answer 9

this limiting(maximum) static frictional force will b equal n opposite to the applied(external) force.

Answer 10

i think applied force will come frm weight W. bt hw. i dont know. still thinking

Answer 11

question 1: normal force is n=mgsina*sina
question 2: f=cn(c=coefficient of friction)
mgsinacosa=c*mgsina*sina
cosa=csina
cota=c
cota=0.48

Answer 12

Sorry, but this is not correct. You cannot "propagate" a force like you are doing with weight in your diagram.

Actually it is way much simpler:

At equilibrium net force equals zero. Then on the vertical, weight and normal reaction by the ground have to cancel out.
Hence N ground = W = mg

Answer 13

Use torque = 0 to find reaction by wall, then you will be able to find friction exerted by the ground.