Question

ABCD is an inscribed quadrilateral whose diagonals intersect at F. Segment AB is parallel to segment DC, as shown below.

The figure shows a quadrilateral ABCD inscribed in a circle. Segment AB is parallel to segment DC. The diagonals AC and BD intersect at F. Angle ACD is 35 degrees and angle DAC is 40 degrees.

Prove that if angle DAC is 40° and angle ACD is 35°, then angle BDA is 70°. Write a two-column proof showing statements and reasons.

Answer 1

@UnkleRhaukus do you know

Answer 2

@mathstudent55

Answer 3

@Hero do you know

Answer 4

@JakeV8

Answer 5

OK, I'm reading it now...

Answer 6

thank you

Answer 7

do you know @mathstudent55

Answer 8

@Chlorophyll can you help

Answer 9

yes

Answer 10

thank you

Answer 11

do you know the answer?? this is my last question

Answer 12

With a two-column proof, first set it up. The first statements are the given. Their reason is given.

Answer 13

yess i know that the first is given but i dont know any of the steps

Answer 14

are u there?

Answer 15

@Hero do you know

Answer 16

Sorry, I'm doing something else right now. Maybe later.

Answer 17

ahh man ok fine

Answer 18

I got it.

Answer 19

St: m<CAB = 35 R: Alt int <s of || lines are congruent

Answer 20

St. m<DBA = 35 R: 2 <s intersect same arc ar congruent

Answer 21

St: m<DBA + m<BAD + m<BDA = 180 R: sum of measures of <s in triangle is 180

Answer 22

St: 35 + 75

Answer 23

St: m<bad = 180 R: Substitution

Answer 24

St: m<BAD = 70 R: Subtraction prop of equality