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Precalculus
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Verify the identity. cos 4x + cos 2x = 2 - 2 sin2 2x - 2 sin2 x
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Is your equation written as such: cos(4x)+cos(2x)=2-2sin(2x)^2-2sin(x)^2 ?
yes
Do you know the double angle identity for cos(2x)?
\[\cos 4x+\cos 2x=\cos2(2x)+1-2\sin ^{2}x=1-2\sin ^{2}2x+1-2\sin ^{2}x\]
no
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\[=2-2\sin ^{2}2x-2\sin ^{2}x\]
Okay, so replace cos(2x) with 1-2sinx^2 and cos(4x) with 1-2sin(2x)^2
ya
Then you have 1-2sin(x)^2+1-2sin(2x)^2=right side.
simplify the variables and you have the left side= to right side.
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Shamim is that the answer?
i c
i m happy to solve this problem
ya its my answer
lhs=rhs
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