Question

Let f(7)=0, f'(7)=14, g(7)=1, g'(7)=1/7. Find h'(7) if h(x)=f(x)/g(x).

Answer 1

So they want you to get an understanding of the product rule with this one.\[\huge h'(x)=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}\]Understand what's going on? :)
From here, you just fill in the pieces that they gave you.

Answer 2

So the answer is 14?

Answer 3

\[\huge h'(x)=\frac{14\cdot 1-0\cdot\frac{1}{7}}{\left(\frac{1}{7}\right)^2}\]
I think you get this when you plug everything in.
Which ends up being.... 14*49 if I did the calculations correctly.

Answer 4

I thought that the denominator is 1, not 1/7.

Answer 5

ah good call :) lol

So 14, yes. good job \^^/

Answer 6

Thank you!