Question

Horizontal asymptote of the function f(x)= 6x^3+17x^2-528/2x^3-14x+321

Answer 1

\[f(x) = 6x^3+17x^2-528/2x^3-14x+321\]

Answer 2

can someone help me please

Answer 3

Horizontal asymptotes
\[=f(x) = \lim_{x \rightarrow \infty} \frac{6x^3+17x^2-528}{2x^3-14x+321}=...\]

Answer 4

yes thats the problem

Answer 5

Divide both the numerator and denominator by x^3

Answer 6

And \[\lim_{x \rightarrow \infty} \frac{1}{x} =0\]

Answer 7

i got 3

Answer 8

Isn't it correct?!

Answer 9

what is the next step , i believe 3 is right

Answer 10

It is 3..

Answer 11

\[\lim_{x \rightarrow \infty} \frac{6x^3+17x^2-528}{2x^3-14x+321}\]\[=\lim_{x \rightarrow \infty} \frac{\frac{6x^3+17x^2-528}{x^3}}{\frac{2x^3-14x+321}{x^3}}\]\[=\lim_{x \rightarrow \infty} \frac{6+\frac{17}{x}-\frac{528}{x^3}}{2-\frac{14}{x^2}+\frac{321}{x^3}}\]Then take the limit