Question

Differentiate by rule...

Answer 1

\[\frac{ x }{ \sqrt{1-x^2} }\]

Answer 2

Looking at it, it seems like a quotient rule, but does it have a chain rule within?

Answer 3

What are you thinking Blufoot?

Answer 4

\[ \frac{ \sqrt{1-x^2} . (1) - (x) . (1-x^2)^{1/2} }{ \sqrt({1-x^2})^2 }\]

Answer 5

Any ideas guys?

Answer 6

yes, first u know that derivative of y=u/v is
y' = (u'v-uv')/v^2
from information above u=x and v=sqrt(1-x^2)
centainly u know that if u=x then u'=1,
now, if v=sqrt(1-x^2) then v'=....

Answer 7

hint : use chain rule
if v=sqrt(f(x)), then v'=f' (x) / 2*sqrt(f(x))

Answer 8

my line above is incorrect?

Answer 9

incorrect

Answer 10

Could you show me that in equation or draw?

Answer 11

ok, first i want to drawing to find derivative of sqrt(1-x^2)