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Mathematics 16 Online
OpenStudy (anonymous):

Prove that the opposite angles of a parallelogram are congruent.

OpenStudy (anonymous):

OpenStudy (anonymous):

Someone please help!

OpenStudy (mathstudent55):

You need a two-column proof. The idea here is to use triangles. You prove the triangles are congruent and then the corresponding parts, the opposite angles of the parallelogram are congruent.

OpenStudy (anonymous):

Whats the given tho i always get confused on that part

OpenStudy (mathstudent55):

Given: Parallelogram ABCD Prove: <1 is congruent to <3 <2 is congruent to <4

OpenStudy (mathstudent55):

St1: Parallelogram ABCD R1: Given

OpenStudy (mathstudent55):

St2. Segment BC is congr to seg AD R2: Opp sides of parallelogram are congruent

OpenStudy (mathstudent55):

St3 Seg CD is congr to seg AB. R3 Opp sides of parallelogram are congr

OpenStudy (mathstudent55):

St 4. Seg BD is congr to seg BD R4 A seg is congruent to itself

OpenStudy (mathstudent55):

st5. triangle BCD is congr to triangle DAB R5 SSS st6 <1 is congr to <3 R6 CPCTC

OpenStudy (mathstudent55):

Now pick two other triangles that are congruent that have angles 2 and 4, prove them congruent and then by CPCTC you get <2 congr to <4

OpenStudy (anonymous):

okay ill try if i need help I'lll let you know

OpenStudy (anonymous):

So would it basically be like <1 and <3 when i try to prove <2 and <4

OpenStudy (anonymous):

@mathstudent55

OpenStudy (mathstudent55):

yes

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