Prove that the opposite angles of a parallelogram are congruent.
Someone please help!
You need a two-column proof. The idea here is to use triangles. You prove the triangles are congruent and then the corresponding parts, the opposite angles of the parallelogram are congruent.
Whats the given tho i always get confused on that part
Given: Parallelogram ABCD Prove: <1 is congruent to <3 <2 is congruent to <4
St1: Parallelogram ABCD R1: Given
St2. Segment BC is congr to seg AD R2: Opp sides of parallelogram are congruent
St3 Seg CD is congr to seg AB. R3 Opp sides of parallelogram are congr
St 4. Seg BD is congr to seg BD R4 A seg is congruent to itself
st5. triangle BCD is congr to triangle DAB R5 SSS st6 <1 is congr to <3 R6 CPCTC
Now pick two other triangles that are congruent that have angles 2 and 4, prove them congruent and then by CPCTC you get <2 congr to <4
okay ill try if i need help I'lll let you know
So would it basically be like <1 and <3 when i try to prove <2 and <4
@mathstudent55
yes
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