Prove that the opposite angles of a parallelogram are congruent.
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OpenStudy (anonymous):
OpenStudy (anonymous):
Someone please help!
OpenStudy (mathstudent55):
You need a two-column proof. The idea here is to use triangles. You prove the triangles are congruent and then the corresponding parts, the opposite angles of the parallelogram are congruent.
OpenStudy (anonymous):
Whats the given tho i always get confused on that part
OpenStudy (mathstudent55):
Given: Parallelogram ABCD
Prove: <1 is congruent to <3
<2 is congruent to <4
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OpenStudy (mathstudent55):
St1: Parallelogram ABCD R1: Given
OpenStudy (mathstudent55):
St2. Segment BC is congr to seg AD R2: Opp sides of parallelogram are congruent
OpenStudy (mathstudent55):
St3 Seg CD is congr to seg AB. R3 Opp sides of parallelogram are congr
OpenStudy (mathstudent55):
St 4. Seg BD is congr to seg BD R4 A seg is congruent to itself
OpenStudy (mathstudent55):
st5. triangle BCD is congr to triangle DAB R5 SSS
st6 <1 is congr to <3 R6 CPCTC
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OpenStudy (mathstudent55):
Now pick two other triangles that are congruent that have angles 2 and 4, prove them congruent and then by CPCTC you get <2 congr to <4
OpenStudy (anonymous):
okay ill try if i need help I'lll let you know
OpenStudy (anonymous):
So would it basically be like <1 and <3 when i try to prove <2 and <4