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Mathematics 13 Online
OpenStudy (anonymous):

Sketch the graph of y=cos(x+pie/2). I don't understand how to do this.

OpenStudy (zehanz):

Do you know how to sketch the graph of y = cosx ?

OpenStudy (anonymous):

yes i do

OpenStudy (zehanz):

The graph of y = cos(x + pi/2) looks a lot like y = cos x. You could see this as follows: cos 0 = 1 is the starting point of the "normal" cos. To get 1 as a result from your function, you need to substitute -pi/2 for x. That means the starting point of cos(x + pi/2) has shifted...

OpenStudy (anonymous):

to the left right?

OpenStudy (zehanz):

Right, to the left!

OpenStudy (anonymous):

So, it would start at -pie/2 and would it go to pie/2 in the positive direction?

OpenStudy (zehanz):

The period (2pi) hasn't changed, so it would end at 3pi/2, exactly 2pi to the right from -pi/2

OpenStudy (anonymous):

oh, ok i get it now thanks!!!

OpenStudy (zehanz):

Thank you too!

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