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Mathematics 15 Online
OpenStudy (anonymous):

What is sinx/cosx + cosx/sinx

OpenStudy (anonymous):

in order to add them, they need to have the same denominator

OpenStudy (anonymous):

so what should the denominator be?

OpenStudy (anonymous):

sin?

OpenStudy (anonymous):

try again

OpenStudy (anonymous):

Cos

OpenStudy (anonymous):

the denominator should be a combination of cos and sin, because one fraction has sin, and the other has cos so the GCF or LCD (i can never remember which) would be "sin(x)cos(x)"

OpenStudy (anonymous):

Im confused... It would be: sinx/sinxcosx + cosx/sinxcosx?

OpenStudy (anonymous):

slow down you cant add them because the denominators are different,one is sin,and the other is cos you need to change both the fractions so that they both have the denominator sinx cosx Lets start by looking at the first fraction \[\frac{\sin x}{\cos{x}}\]in order to get teh denominator to become cos x sinx, we need to multiply a sin x to the denominator, but you can't just multiply 1/ sin x, otherwise you would get a completely different fraction the solution would be to multiply 1 because 1 times any number will be the number \[1=\frac{\sin x}{\sin x}\] \[\frac{\sin x}{\cos{x}}*1=\frac{\sin x}{\cos{x}}*\frac{\sin x}{\sin x}= \frac{{\sin}^2 x}{\sin x \cos x}\] now we need to do the same process for the other fraction

OpenStudy (anonymous):

so what do you think the other fraction will look like?

OpenStudy (anonymous):

cos^2/sinxcosx

OpenStudy (anonymous):

right, good job now since they both have the same denominator, you can add up the numerators \[\frac{\sin^2 x}{\sin x \cos x} + \frac{\cos^2 x}{\sin x \cos x}\] \[\frac{\cos^2 x+\sin^2 x}{\sin x \cos x}\]

OpenStudy (anonymous):

also know the trig identity \[\sin^2 x+\cos^2 x =1\]

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